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0.01x^2-x+16=0
We add all the numbers together, and all the variables
0.01x^2-1x+16=0
a = 0.01; b = -1; c = +16;
Δ = b2-4ac
Δ = -12-4·0.01·16
Δ = 0.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{0.36}}{2*0.01}=\frac{1-\sqrt{0.36}}{0.02} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{0.36}}{2*0.01}=\frac{1+\sqrt{0.36}}{0.02} $
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